Overview
- Bode Sparrow announced his commitment to the University of Oklahoma on Friday, June 26, 2026, choosing the Sooners over finalists BYU, Oregon and Utah.
- The 6-foot-2, 195-pound Sparrow is a four-star two-way player who had 83 catches for 1,218 yards and 16 receiving touchdowns last season while totaling 71 tackles and seven interceptions on defense.
- Recruiting services list Sparrow among the class’ top athletes with 247Sports placing him at No. 82 overall and No. 1 in Utah and the USA TODAY composite ranking him inside the top 75.
- Sparrow had offers from more than two dozen Power Four programs and visited Hawaiʻi during his recruitment, reflecting wide national interest in his versatility.
- His pledge gives Oklahoma its 26th commitment for 2027, makes him roughly the program’s fifth-highest-rated commit, and further cements the Sooners’ top-five class while pulling a top in‑state Utah prospect to an out‑of‑state Power program.